49=x^2/(.3-x)(.1-x)

Solution for 49=x^2/(.3-x)(.1-x) equation:

49=x^2/(.3-x)(.1-x)

We move all terms to the left:

49-(x^2/(.3-x)(.1-x))=0


Domain of the equation: (.3-x)(.1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(.1-x)!=-.3

x∈R


We add all the numbers together, and all the variables

-(x^2/(-1x+0.3)(-1x+0.1))+49=0

We multiply parentheses ..

-(x^2/(+x^2-0.1x-0.3x+0.03))+49=0

We multiply all the terms by the denominator


-(x^2+49*(+x^2-0.1x-0.3x+0.03))=0


We calculate terms in parentheses: -(x^2+49*(+x^2-0.1x-0.3x+0.03)), so:

x^2+49*(+x^2-0.1x-0.3x+0.03)

We multiply parentheses

x^2+49x^2+0x+0x+1.47

We add all the numbers together, and all the variables

50x^2+2x+1.47

Back to the equation:

-(50x^2+2x+1.47)


We get rid of parentheses

-50x^2-2x-1.47=0

a = -50; b = -2; c = -1.47;
Δ = b2-4ac
Δ = -22-4·(-50)·(-1.47)
Δ = -290
Delta is less than zero, so there is no solution for the equation